Warning: I may have made a mistake!

The answer in the comments to the [post](https://www.reddit.com/r/copypasta/comments/5cmjm7/request_the_bee_movie_script_but_every_time_the/) about the Bee movie length is correct, I believe, but when I first read the request, I thought something different. I made the assumption that the word “Bee” is replaced with the script minus that one mention. That script then undergoes the same treatment until “Bee” is no longer found in the text.

For example, if the script only contained one reference to the word “Bee”, then the word would be replaced with the script minus that one word (roughly a script twice as big). Continuing, if the script contained two references to the word “Bee”, then both of those occurences would be replaced with the script that originally contained one reference. Therefore, the final script would be roughly 5 times as big (1 + 2 + 2 since the one reference script ended up twice as big).

Going with this, I ended up with this formula. Given ***x*** occurrences of a phrase ***w*** words long in a script that is ***s*** **+** ***w*** \* ***x*** words long, the length of the final script should be:

***f(x, w, s) = s + (s + w) * ∑(k=(1, x)) (x!)/((k-1)!)***

That is, the final word count equals the length of the script plus the product of the sum of the length of the script and the length of the phrase being replaced and the finite sum from 1 to the number of occurrences of the phrase of the quotient of the factorial of the number of occurrences of the phrase divided by the factorial of the current index minus one.

That was wordy.

In any case, using the above numbers, Wolfram Alpha gives me the following:

***f(*****173, 1, 8938*****) =*****1664811848415122521450839402439708157106518851064460429581637895278232360270925322776558825176125086330867463300504823041487705878131499934972682837925625292718780341594239334404485331371572824176398048406494719053540775233918966603172467295537077549265700642109335925098259400032686926811934007243009741902990079905527323283181710273761492045084140601422968739093**

In easier terms, that is approximately **1.66 × 10^199 words**.

Wolfram provides a handy conversion of 250 words per manuscript page. Therefore, we have roughly **6.64 × 10^196 pages** in our new script. That is equal to a stack of paper **2.656×10^194 inches** high. To get a measure of scale, this is **7.7×10^165 times the diameter of the observable universe**.

Audiobooks are recommended to be read at 150 – 160 words per minute (according to [this wikipedia article](https://en.wikipedia.org/wiki/Words_per_minute#Speech_and_listening)). Recording this script as an audio book would result in a recording that would be **1.4×10^181 times the current age of the universe** and would require **2.491×10^193 GB** to store at the regular 32kbps encoding.

tl;dr Don’t do this. I like the universe not being a black hole.